138013
YIMBY
Tourist
138017
138019
again
again
M
MrsShemon
Guest
138021
690 appears once every 1000 counts, => 138,000 ÷ 1000 = 138, but it appears 10 times in a row,=> 138 × 10 = 1,380.
6,900 appear once every 10,000 counts, => 138,000 ÷ 10,000 = 13,8, 13 as we have not had 146900 yet, but it appears 100 times in a row, => 13 × 100 = 1300. Edit: forgot the first 6,900, => 14 × 100 = 1400.
69,000 appears once every 100,000 counts, = 1, but it appears 1,000 times in a row, = 1,000.
1,380 + 1,380 +1,300 1,400 + 1,000 = 5,060 5,160 times have "69" appeared so far.
69 appears once every 100 counts, => 138,000 ÷ 100 = 1,380.
690 appears once every 1000 counts, => 138,000 ÷ 1000 = 138, but it appears 10 times in a row,=> 138 × 10 = 1,380.
6,900 appear once every 10,000 counts, => 138,000 ÷ 10,000 =
69,000 appears once every 100,000 counts, = 1, but it appears 1,000 times in a row, = 1,000.
1,380 + 1,380 +
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M
MrsShemon
Guest
138023
Yay! Finally I got something positive from my Asian genes.
Yay! Finally I got something positive from my Asian genes.
M
MrsShemon
Guest
138025
Do tell.
Do tell.
138027
I tried to cheat earlier and searched for "how many consecutive times does 69 appear in 13,800?" but unfortunately I couldn't find much. It kept trying to give me the number of 69s in the first 10,000 digits of pi... which is not what I had asked for! Lol
I tried to cheat earlier and searched for "how many consecutive times does 69 appear in 13,800?" but unfortunately I couldn't find much. It kept trying to give me the number of 69s in the first 10,000 digits of pi... which is not what I had asked for! Lol
138028
Dont you have to account for the times where they overlap? For example, you have already accounted for a 69 when doing a number such as 16969, when you did 1 69 every 100. So you would have to subtract that one from the overall count when you accounted for the consecutive 69s throughout 16900-16999
Dont you have to account for the times where they overlap? For example, you have already accounted for a 69 when doing a number such as 16969, when you did 1 69 every 100. So you would have to subtract that one from the overall count when you accounted for the consecutive 69s throughout 16900-16999
M
MrsShemon
Guest
138029
I started with making an equation in Excel, but then realized that I just needed to figure out how often they occured, way easier than building a mathematical model in Excel.
But I can calculate how many that are 69's and disregarding when 69 appears multiple times if you want?
I started with making an equation in Excel, but then realized that I just needed to figure out how often they occured, way easier than building a mathematical model in Excel.
That is very much correct. I have only calculated how many times a 9 follows a 6 up until 138,000.
But I can calculate how many that are 69's and disregarding when 69 appears multiple times if you want?
M
MrsShemon
Guest
138031
Okey:
As each 6,900 have one 6969, we must subtract 1 from each 6,900 occuring = 14
As 69,000 have one 690 and ten 69 we have 11 double 69s.
=> 5,160 - 25 = 5,135
Okey:
As each 6,900 have one 6969, we must subtract 1 from each 6,900 occuring = 14
As 69,000 have one 690 and ten 69 we have 11 double 69s.
=> 5,160 - 25 = 5,135
M
MrsShemon
Guest
138033
You probably missed counting 6,900 and just included the other x/xx6,900 as I did at first, real easy to miss when just dividing to find out how many times something occurs.
You probably missed counting 6,900 and just included the other x/xx6,900 as I did at first, real easy to miss when just dividing to find out how many times something occurs.
M
MrsShemon
Guest
138035
But if we do build a mathematical model in Excel, we can put any number we want and figure out how often any consecutive combinations of numbers occur.
But now that Dane mentioned that we can't count the times those consecutive combinations appear multiple times, the building of that model suddenly became a lot more difficult with a lot more equations and variables needed.
But if we do build a mathematical model in Excel, we can put any number we want and figure out how often any consecutive combinations of numbers occur.
But now that Dane mentioned that we can't count the times those consecutive combinations appear multiple times, the building of that model suddenly became a lot more difficult with a lot more equations and variables needed.
M
MrsShemon
Guest
138037
For my two calculations here today, it was just brain counting and keeping track of what I did by reading what I had written so far.
Excel is something I use rather often. A couple of sheets with whatever variables that exist in any given location, some models to calculate how those variables effects each other or something else and finally a model for regression analysis on all already existing calculations to predict variables or other things using what data you have from a location.
Better programs exist, but with Excel you can do all those things in the same program.
Really easy to print out all your data and make diagrams too, so I think that it is a pretty good software.
For my two calculations here today, it was just brain counting and keeping track of what I did by reading what I had written so far.
Excel is something I use rather often. A couple of sheets with whatever variables that exist in any given location, some models to calculate how those variables effects each other or something else and finally a model for regression analysis on all already existing calculations to predict variables or other things using what data you have from a location.
Better programs exist, but with Excel you can do all those things in the same program.
Really easy to print out all your data and make diagrams too, so I think that it is a pretty good software.
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